What is the extreme f(x)=2x^3-6x+2 ?

The extreme f(x)=2x^3-6x+2 is Maximum(-1,6),Minimum(1,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^3-6x+2

extreme points

f (x) = 2 x^{3} - 6 x + 2

Maximum (- 1, 6), Minimum (1, - 2)

Solution steps

f^{'} (x) = 6 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

2 x^{3} - 6 x + 2 : 6

Maximum (- 1, 6)

Plug

x = 1

into

2 x^{3} - 6 x + 2 : - 2

Minimum (1, - 2)

Maximum (- 1, 6), Minimum (1, - 2)

6 x^{5} - 10 x^{3}

f (x, y) = 2 x^{3} + 4 x y - y^{2}

f (x, y) = x^{3} + y^{3} - 36 x y

f (x) = \frac{x - 2}{x ^{3}}

f (x) = x^{2} - 2 x + 1, 0 \leq x \leq 3

What is the extreme f(x)=2x^3-6x+2 ?
The extreme f(x)=2x^3-6x+2 is Maximum(-1,6),Minimum(1,-2)