What is the extreme f(x,y)=y^2+xy+3x+2y+5 ?

The extreme f(x,y)=y^2+xy+3x+2y+5 is Saddle(4,-3)

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extreme f(x,y)=y^2+xy+3x+2y+5

extreme points

f (x, y) = y^{2} + x y + 3 x + 2 y + 5

Saddle (4, - 3)

Solution steps

Find the critical points:

(4, - 3)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(4, - 3) :

Saddle

Saddle (4, - 3)

E, E = \frac{I R}{I}

f (x) = 3 + 8 x^{3} - y^{3} - 12 x y

y (x, t) = x (3 t - 9)

f (x) = x^{4} + 8 x^{3} - 2

f (x) = 2 x^{2} + 3 x y + 4 y^{2} + 5 x - 2 y

What is the extreme f(x,y)=y^2+xy+3x+2y+5 ?
The extreme f(x,y)=y^2+xy+3x+2y+5 is Saddle(4,-3)