What is the extreme f(t)=(t-2)u(t+5) ?

The extreme f(t)=(t-2)u(t+5) is Saddle(2,0),Saddle(-5,0)

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extreme f(t)=(t-2)u(t+5)

extreme points

f (t) = (t - 2) u (t + 5)

Saddle (2, 0), Saddle (- 5, 0)

Solution steps

Find the critical points:

(2, 0), (- 5, 0)

\frac{\partial ^{2} f}{\partial t ^{2}} = 0

D (t, u) = - 4 t^{2} - 12 t - 9

Check the sign of at each critical point

Check critical point

(2, 0) :

Saddle

Check critical point

(- 5, 0) :

Saddle

Saddle (2, 0), Saddle (- 5, 0)

f (x) = sin^{2} (x), 0 \leq x \leq 2 π

f (x, y) = - 4 x^{2} + 7 x y - 3 y^{2} + x + y

- 0.05 x^{2} + 71 x + 200

4 x^{2} - 2 y^{2} + 2 x y

g (x, y) = x c + y

What is the extreme f(t)=(t-2)u(t+5) ?
The extreme f(t)=(t-2)u(t+5) is Saddle(2,0),Saddle(-5,0)