What is the extreme f(x)=-0.002x^2+4.4x-10 ?

The extreme f(x)=-0.002x^2+4.4x-10 is Maximum(1100,2410)

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extreme f(x)=-0.002x^2+4.4x-10

extreme points

f (x) = - 0.002 x^{2} + 4.4 x - 10

Maximum (1100, 2410)

Solution steps

f^{'} (x) = - 0.004 x + 4.4

Find intervals:

Increasing

: - \infty < x < 1100,

Decreasing

: 1100 < x < \infty

Plug

x = 1100

into

- 0.002 x^{2} + 4.4 x - 10 : 2410

Maximum (1100, 2410)

f (x) = x^{\frac{2}{5}} (x - 8)

f (x) = \frac{sin ( x )}{2 + cos ( x )}

f (x) = \frac{3 ( x ^{2} + 1 )}{x ^{2} - x + 1}

f (x) = (\frac{x}{2}) + \frac{1}{x}

f (x) = x^{\frac{3}{2}} - x^{\frac{1}{2}}, 0 \leq x \leq 1

What is the extreme f(x)=-0.002x^2+4.4x-10 ?
The extreme f(x)=-0.002x^2+4.4x-10 is Maximum(1100,2410)