What is the extreme f(x)=3x^{2/3}+2x-1 ?

The extreme f(x)=3x^{2/3}+2x-1 is Minimum(-1,0),Maximum(0,-1)

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extreme f(x)=3x^{2/3}+2x-1

extreme points

f (x) = 3 x^{\frac{2}{3}} + 2 x - 1

Minimum (- 1, 0), Maximum (0, - 1)

Solution steps

f^{'} (x) = \frac{2}{x ^{\frac{1}{3}}} + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

3 x^{\frac{2}{3}} + 2 x - 1 : 0

Minimum (- 1, 0)

Plug

x = 0

into

3 x^{\frac{2}{3}} + 2 x - 1 : - 1

Maximum (0, - 1)

Minimum (- 1, 0), Maximum (0, - 1)

f (x) = x^{3} + x^{2} - x + 2

f (x, y) = \frac{y}{x + y ^{3}}

f (x, y) = x^{3} + 12 x y^{2} - 15 x - 24 x

f (x) = sin (x) - cos^{2} (x), 0 \leq x \leq 2 π

f (x, y) = e^{x^{2} - y^{2}}

What is the extreme f(x)=3x^{2/3}+2x-1 ?
The extreme f(x)=3x^{2/3}+2x-1 is Minimum(-1,0),Maximum(0,-1)