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Popular >

extreme (2x^2)/(x^2-1)

Solution

extreme points

\frac{2 x ^{2}}{x ^{2} - 1}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{4 x}{( x ^{2} - 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

\frac{2 x ^{2}}{x ^{2} - 1} : 0

Maximum (0, 0)

Popular Examples

extreme f(x,y)=2x-x^2+2y^2-y^4 extreme points

f (x, y) = 2 x - x^{2} + 2 y^{2} - y^{4}

extreme f(x)=x^3-9x^2+24 extreme points

f (x) = x^{3} - 9 x^{2} + 24

extreme (4x^2)/(x^2-9)extreme points

\frac{4 x ^{2}}{x ^{2} - 9}

extreme f(x,y)=e^{(x^2+0.5y^2-5xy-3x)}extreme points

f (x, y) = e^{(x^{2} + 0.5 y^{2} - 5 x y - 3 x)}

extreme f(x)=x^2-15x+56 extreme points

f (x) = x^{2} - 15 x + 56

Frequently Asked Questions (FAQ)

What is the extreme (2x^2)/(x^2-1) ?
The extreme (2x^2)/(x^2-1) is Maximum(0,0)