What is the extreme-(((2))/((x^{(2))-9)}) ?

The extreme-(((2))/((x^{(2))-9)}) is Minimum(0, 2/9)

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extreme-(((2))/((x^{(2))-9)})

extreme points

- (\frac{( 2 )}{( x ^{(2)} - 9 )})

Minimum (0, \frac{2}{9})

Solution steps

f^{'} (x) = \frac{4 x}{( x ^{2} - 9 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 0

into

- \frac{2}{x ^{2} - 9} : \frac{2}{9}

Minimum (0, \frac{2}{9})

f (x, y) = 121 - x^{2} - y^{2}

10 x^{2} + y^{2} - 6 x y - 24 x

f (x, y) = x^{3} - 5 x^{2} + 3 y^{2} + 3 x + 1

f (x, y) = x^{4} + y^{4} - 2 x y

f (x) = x^{4} + 4 x^{3} + 4 x^{2}

What is the extreme-(((2))/((x^{(2))-9)}) ?
The extreme-(((2))/((x^{(2))-9)}) is Minimum(0, 2/9)