What is the extreme f(x)=-2x^4+16x^3-26 ?

The extreme f(x)=-2x^4+16x^3-26 is Saddle(0,-26),Maximum(6,838)

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extreme f(x)=-2x^4+16x^3-26

extreme points

f (x) = - 2 x^{4} + 16 x^{3} - 26

Saddle (0, - 26), Maximum (6, 838)

Solution steps

f^{'} (x) = - 8 x^{3} + 48 x^{2}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < 6,

Decreasing

: 6 < x < \infty

Plug

x = 0

into

- 2 x^{4} + 16 x^{3} - 26 : - 26

Saddle (0, - 26)

Plug

x = 6

into

- 2 x^{4} + 16 x^{3} - 26 : 838

Maximum (6, 838)

Saddle (0, - 26), Maximum (6, 838)

f (x) = (x - 5)^{2} + 3

f (x, y) = 1 - x + y

f (x, y) = x^{2} y - 2 x y^{2} + 8 y^{3}

f (x y) = 3 x^{4} + 8 x^{3} - 18 x^{2} + 6 y^{2} + 12 y - 4

f (x) = x^{3} + 9 x^{2} + b

What is the extreme f(x)=-2x^4+16x^3-26 ?
The extreme f(x)=-2x^4+16x^3-26 is Saddle(0,-26),Maximum(6,838)