What is the extreme f(x)=(5x-2)/(x^2-10x+25) ?

The extreme f(x)=(5x-2)/(x^2-10x+25) is Minimum(-21/5 ,-25/92)

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extreme f(x)=(5x-2)/(x^2-10x+25)

extreme points

f (x) = \frac{5 x - 2}{x ^{2} - 10 x + 25}

Minimum (- \frac{21}{5}, - \frac{25}{92})

Solution steps

f^{'} (x) = - \frac{5 x + 21}{( x - 5 ) ^{3}}

Find intervals:

Decreasing

: - \infty < x < - \frac{21}{5},

Increasing

: - \frac{21}{5} < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = - \frac{21}{5}

into

\frac{5 x - 2}{x ^{2} - 10 x + 25} : - \frac{25}{92}

Minimum (- \frac{21}{5}, - \frac{25}{92})

p (a, c) = a + 5 + c

f (x) = \frac{( e ^{x^{2}} + e ^{2 - x^{2}} )}{5}

f (x, y) = 4 y^{2} - 6 x y

f (x, y) = x^{2} + 6 x y + 12 y^{2} - 6 x + 10 y - 2

f (x) = 2 sin (x) + sin^{2} (x)

What is the extreme f(x)=(5x-2)/(x^2-10x+25) ?
The extreme f(x)=(5x-2)/(x^2-10x+25) is Minimum(-21/5 ,-25/92)