What is the extreme f(x)=2x^3+6x^2-5 ?

The extreme f(x)=2x^3+6x^2-5 is Maximum(-2,3),Minimum(0,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^3+6x^2-5

extreme points

f (x) = 2 x^{3} + 6 x^{2} - 5

Maximum (- 2, 3), Minimum (0, - 5)

Solution steps

f^{'} (x) = 6 x^{2} + 12 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

2 x^{3} + 6 x^{2} - 5 : 3

Maximum (- 2, 3)

Plug

x = 0

into

2 x^{3} + 6 x^{2} - 5 : - 5

Minimum (0, - 5)

Maximum (- 2, 3), Minimum (0, - 5)

f (x) = 3 x^{2} - 5 x - 4

f (x) = (x^{2} - x)^{\frac{2}{3}}

f (x) = x + 1

f (x) = x e^{- 5 x^{2}}

f (x) = x^{3} - 12 x^{2} + 1

What is the extreme f(x)=2x^3+6x^2-5 ?
The extreme f(x)=2x^3+6x^2-5 is Maximum(-2,3),Minimum(0,-5)