en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^2+4x+6

Solution

extreme points

f (x) = x^{2} + 4 x + 6

Solution

Minimum (- 2, 2)

Solution steps

f^{'} (x) = 2 x + 4

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

x^{2} + 4 x + 6 : 2

Minimum (- 2, 2)

Popular Examples

extreme 1-x^{2/3}extreme points

1 - x^{\frac{2}{3}}

extreme f(x,y)=x^2-0.5y^2+3x extreme points

f (x, y) = x^{2} - 0.5 y^{2} + 3 x

extreme f(x)=8sin(|x|),-2pi<= x<= 2pi extreme points

f (x) = 8 sin (∣ x ∣), - 2 π \leq x \leq 2 π

extreme 18cos(θ)+9sin^2(θ),-pi<= θ<= pi extreme points

18 cos (θ) + 9 sin^{2} (θ), - π \leq θ \leq π

extreme f(x,y)=x^2-2x+(y^2)/2-2y extreme points

f (x, y) = x^{2} - 2 x + \frac{y ^{2}}{2} - 2 y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+4x+6 ?
The extreme f(x)=x^2+4x+6 is Minimum(-2,2)