What is the extreme f(x)=2x^3-6x^2+4 ?

The extreme f(x)=2x^3-6x^2+4 is Maximum(0,4),Minimum(2,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^3-6x^2+4

extreme points

f (x) = 2 x^{3} - 6 x^{2} + 4

Maximum (0, 4), Minimum (2, - 4)

Solution steps

f^{'} (x) = 6 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

2 x^{3} - 6 x^{2} + 4 : 4

Maximum (0, 4)

Plug

x = 2

into

2 x^{3} - 6 x^{2} + 4 : - 4

Minimum (2, - 4)

Maximum (0, 4), Minimum (2, - 4)

f (x) = 3 x - 9 x^{\frac{1}{3}}

g (x, y) = c x + y x

x^{3} + 6 x^{2} + 9 x

f (x) = \frac{x ^{2} ( x - 1 )}{x + 2}

f (x) = 2 x^{3} - 3 x^{2} - 36 x + 1

What is the extreme f(x)=2x^3-6x^2+4 ?
The extreme f(x)=2x^3-6x^2+4 is Maximum(0,4),Minimum(2,-4)