What is the extreme 100+1/2 x+(1800)/x ?

The extreme 100+1/2 x+(1800)/x is Maximum(-60,40),Minimum(60,160)

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extreme 100+1/2 x+(1800)/x

extreme points

100 + \frac{1}{2} x + \frac{1800}{x}

Maximum (- 60, 40), Minimum (60, 160)

Solution steps

f^{'} (x) = - \frac{1800}{x ^{2}} + \frac{1}{2}

Find intervals:

Increasing

: - \infty < x < - 60,

Decreasing

: - 60 < x < 0,

Decreasing

: 0 < x < 60,

Increasing

: 60 < x < \infty

Plug

x = - 60

into

100 + \frac{1}{2} x + \frac{1800}{x} : 40

Maximum (- 60, 40)

Plug

x = 60

into

100 + \frac{1}{2} x + \frac{1800}{x} : 160

Minimum (60, 160)

Maximum (- 60, 40), Minimum (60, 160)

- cos (x)

f (x) = 3 e^{x} - e^{3 x}

f (x, y) = x^{3} + 6 x y + 2 y^{2} + 6 x

f (x, y) = 5 x^{2} + 3 x y + y^{2}

f (x, y) = x + y - x y

What is the extreme 100+1/2 x+(1800)/x ?
The extreme 100+1/2 x+(1800)/x is Maximum(-60,40),Minimum(60,160)