What is the extreme f(x)=3x^3-36x+3 ?

The extreme f(x)=3x^3-36x+3 is Maximum(-2,51),Minimum(2,-45)

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extreme f(x)=3x^3-36x+3

extreme points

f (x) = 3 x^{3} - 36 x + 3

Maximum (- 2, 51), Minimum (2, - 45)

Solution steps

f^{'} (x) = 9 x^{2} - 36

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

3 x^{3} - 36 x + 3 : 51

Maximum (- 2, 51)

Plug

x = 2

into

3 x^{3} - 36 x + 3 : - 45

Minimum (2, - 45)

Maximum (- 2, 51), Minimum (2, - 45)

f (x, y) = 1 + 2 x y

f (x, y) = 2 x + y + \frac{2}{x} - \frac{y ^{2}}{2}

f (x, y) = 2 x y - x^{3} - y^{2}

f (x) = 3 x^{4} + 8 x^{3} - 6 x^{2} - 24 x

What is the extreme f(x)=3x^3-36x+3 ?
The extreme f(x)=3x^3-36x+3 is Maximum(-2,51),Minimum(2,-45)