en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y=(x^3+4)/(x^2)

Solution

extreme points

y = \frac{x ^{3} + 4}{x ^{2}}

Solution

Minimum (2, 3)

Solution steps

f^{'} (x) = \frac{x ^{3} - 8}{x ^{3}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

\frac{x ^{3} + 4}{x ^{2}} : 3

Minimum (2, 3)

Popular Examples

extreme f(x)=sqrt(x^2-9)extreme points

f (x) = x^{2} - 9

extreme f(x)=sqrt(x^2-2)extreme points

f (x) = x^{2} - 2

extreme f(x)=sqrt(x^2-4)extreme points

f (x) = x^{2} - 4

derivative of Insqrt((x+1/(x-1)))

\frac{d}{d x} (I n \frac{x + 1}{x - 1})

extreme x^4-2x^3+2 extreme points

x^{4} - 2 x^{3} + 2

Frequently Asked Questions (FAQ)

What is the extreme y=(x^3+4)/(x^2) ?
The extreme y=(x^3+4)/(x^2) is Minimum(2,3)