What is the extreme f(x,y)=e^y-ye^x ?

The extreme f(x,y)=e^y-ye^x is Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=e^y-ye^x

extreme points

f (x, y) = e^{y} - y e^{x}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = e^{y}

D (x, y) = - e^{x + y} y - e^{2 x}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = 3 x^{2} + 5 x - 4

f (x) = - \frac{1}{x ^{2}}

f (x, y) = x^{2} + x y - (7 + 1) y - (8 + 1) x + 1

4^{x + 1} - 3

f (x) = x^{2} + 10 + 24

What is the extreme f(x,y)=e^y-ye^x ?
The extreme f(x,y)=e^y-ye^x is Saddle(0,0)