What is the extreme f(x,y)=ln|4x^2+18y^2-36| ?

The extreme f(x,y)=ln|4x^2+18y^2-36| is None

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extreme f(x,y)=ln|4x^2+18y^2-36|

extreme points

f (x, y) = ln 4 x^{2} + 18 y^{2} - 36

None

Solution steps

Find the critical points:

None

f (x)

has no critical points, therefore there are no extreme points

None

f (x) = 8 - 2 x + 4 y - x^{2} - 4 y^{2}

f (x, y) = x^{2} + 2 x y + 2 y^{2} - 6 x + 10 y + 2

f (x) = \frac{x ^{2}}{1 - x}

f (x) = 4 - x^{2}, - 1 \leq x \leq 2

f (x) = \frac{1}{1 + ∣ x ∣} + \frac{1}{1 + ∣ x - 2 ∣}

What is the extreme f(x,y)=ln|4x^2+18y^2-36| ?
The extreme f(x,y)=ln|4x^2+18y^2-36| is None