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Popular >

extreme f(x)=ln(7-2x^2)

Solution

extreme points

f (x) = ln (7 - 2 x^{2})

Solution

Maximum (0, ln (7))

Solution steps

f^{'} (x) = - \frac{4 x}{7 - 2 x ^{2}}

Find intervals:

Increasing

: - \frac{7}{2} < x < 0,

Decreasing

: 0 < x < \frac{7}{2}

Plug

x = 0

into

ln (7 - 2 x^{2}) : ln (7)

Maximum (0, ln (7))

Popular Examples

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f (x) = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} - 6 x + 4

extreme x/(x^2+13x+36)extreme points

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extreme f(x)=2x^3-12x^2+6 extreme points

f (x) = 2 x^{3} - 12 x^{2} + 6

extreme f(x)=2x^3-12x^2+4 extreme points

f (x) = 2 x^{3} - 12 x^{2} + 4

extreme f(x)=x^3-6x^2+12x+4 extreme points

f (x) = x^{3} - 6 x^{2} + 12 x + 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(7-2x^2) ?
The extreme f(x)=ln(7-2x^2) is Maximum(0,ln(7))