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Popular >

extreme f(x)=x^3-6x^2+12x-3

Solution

extreme points

f (x) = x^{3} - 6 x^{2} + 12 x - 3

Solution

Saddle (2, 5)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 12

Find intervals:

Increasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{3} - 6 x^{2} + 12 x - 3 : 5

Saddle (2, 5)

Popular Examples

extreme f(x)=x^3-x+1 extreme points

f (x) = x^{3} - x + 1

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f (x, y) = 9 x^{2} + 2 y^{2} - x y^{2}

extreme f(x)= 1/x ,1<x<3 extreme points

f (x) = \frac{1}{x}, 1 < x < 3

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f (x, y) = x^{2} - y^{2} + 6 x y + 4 x - 8 y + 2

extreme f(x,y)=xy^2+12x^3y-xy extreme points

f (x, y) = x y^{2} + 12 x^{3} y - x y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3-6x^2+12x-3 ?
The extreme f(x)=x^3-6x^2+12x-3 is Saddle(2,5)