What is the extreme f(x)=3x^3-9x^2 ?

The extreme f(x)=3x^3-9x^2 is Maximum(0,0),Minimum(2,-12)

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extreme f(x)=3x^3-9x^2

extreme points

f (x) = 3 x^{3} - 9 x^{2}

Maximum (0, 0), Minimum (2, - 12)

Solution steps

f^{'} (x) = 9 x^{2} - 18 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

3 x^{3} - 9 x^{2} : 0

Maximum (0, 0)

Plug

x = 2

into

3 x^{3} - 9 x^{2} : - 12

Minimum (2, - 12)

Maximum (0, 0), Minimum (2, - 12)

f (x) = - \frac{2}{5} x^{5} + 5 x^{4} - 16 x^{3} - 19

f (x) = - 0.2 x^{3} + 969 x - 870

f (x) = x^{4} + x^{3} - 4 x^{2} - 4 x

f (x) = 7 x + 1 + \frac{2}{x - 2}

f (x) = x^{3} + 2 x y - 2 x - 4 y

What is the extreme f(x)=3x^3-9x^2 ?
The extreme f(x)=3x^3-9x^2 is Maximum(0,0),Minimum(2,-12)