What is the extreme f(x)=x^3-5x^2-8x+3 ?

The extreme f(x)=x^3-5x^2-8x+3 is Maximum(-2/3 , 157/27),Minimum(4,-45)

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extreme f(x)=x^3-5x^2-8x+3

extreme points

f (x) = x^{3} - 5 x^{2} - 8 x + 3

Maximum (- \frac{2}{3}, \frac{157}{27}), Minimum (4, - 45)

Solution steps

f^{'} (x) = 3 x^{2} - 10 x - 8

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 5 x^{2} - 8 x + 3 : \frac{157}{27}

Maximum (- \frac{2}{3}, \frac{157}{27})

Plug

x = 4

into

x^{3} - 5 x^{2} - 8 x + 3 : - 45

Minimum (4, - 45)

Maximum (- \frac{2}{3}, \frac{157}{27}), Minimum (4, - 45)

f (x) = 2 x^{2} + 3 y^{2} - 4 x - 12 y + 13

f (x) = 5 - 6 x^{2} - 2 x^{3}

\frac{3}{2} x^{2} + x^{3} + 3 y^{2}

f (x) = \frac{3}{x}

f (x, y) = (9 + x y) (x + y)

What is the extreme f(x)=x^3-5x^2-8x+3 ?
The extreme f(x)=x^3-5x^2-8x+3 is Maximum(-2/3 , 157/27),Minimum(4,-45)