What is the extreme f(x)=-x^3-9x^2-15x+1 ?

The extreme f(x)=-x^3-9x^2-15x+1 is Minimum(-5,-24),Maximum(-1,8)

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extreme f(x)=-x^3-9x^2-15x+1

extreme points

f (x) = - x^{3} - 9 x^{2} - 15 x + 1

Minimum (- 5, - 24), Maximum (- 1, 8)

Solution steps

f^{'} (x) = - 3 x^{2} - 18 x - 15

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < - 1,

Decreasing

: - 1 < x < \infty

Plug

x = - 5

into

- x^{3} - 9 x^{2} - 15 x + 1 : - 24

Minimum (- 5, - 24)

Plug

x = - 1

into

- x^{3} - 9 x^{2} - 15 x + 1 : 8

Maximum (- 1, 8)

Minimum (- 5, - 24), Maximum (- 1, 8)

f (x, y) = 4 y^{2} + 5 x^{2} - 9 y + 8 x - 19

f (x) = 8 x^{2} + 8 x y + 10 y^{2} - 24 x - 28 y + 27

f (x) = x - 4 ln (x)

\frac{d}{d x} (\frac{x y}{x ^{2} - 1})

f (x) = x^{3} + 3 x^{2} - 45 x + 4

What is the extreme f(x)=-x^3-9x^2-15x+1 ?
The extreme f(x)=-x^3-9x^2-15x+1 is Minimum(-5,-24),Maximum(-1,8)