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Popular >

extreme f(x)=2x^2-4x+2

Solution

extreme points

f (x) = 2 x^{2} - 4 x + 2

Solution

Minimum (1, 0)

Solution steps

f^{'} (x) = 4 x - 4

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

2 x^{2} - 4 x + 2 : 0

Minimum (1, 0)

Popular Examples

extreme f(x)=x^3-9x^2+4 extreme points

f (x) = x^{3} - 9 x^{2} + 4

extreme f(x)= 1/(sqrt(16-x^2+4y^2))extreme points

f (x) = \frac{1}{16 - x ^{2} + 4 y ^{2}}

extreme f(x)=x^3(1-x)^2 extreme points

f (x) = x^{3} (1 - x)^{2}

extreme y=x^{2/3}(6-x)^{1/3}extreme points

y = x^{\frac{2}{3}} (6 - x)^{\frac{1}{3}}

extreme f(x)=(x^2-4)^7 extreme points

f (x) = (x^{2} - 4)^{7}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-4x+2 ?
The extreme f(x)=2x^2-4x+2 is Minimum(1,0)