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Popular >

extreme f(x)=4x^2-8x+16

Solution

extreme points

f (x) = 4 x^{2} - 8 x + 16

Solution

Minimum (1, 12)

Solution steps

f^{'} (x) = 8 x - 8

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

4 x^{2} - 8 x + 16 : 12

Minimum (1, 12)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2-8x+16 ?
The extreme f(x)=4x^2-8x+16 is Minimum(1,12)