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Popular >

extreme f(x)=(4x-8)/(x^3)

Solution

extreme points

f (x) = \frac{4 x - 8}{x ^{3}}

Solution

Maximum (3, \frac{4}{27})

Solution steps

f^{'} (x) = \frac{8 ( - x + 3 )}{x ^{4}}

Find intervals:

Increasing

: - \infty < x < 0,

Increasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = 3

into

\frac{4 x - 8}{x ^{3}} : \frac{4}{27}

Maximum (3, \frac{4}{27})

Popular Examples

extreme f(x)=3x(x-5)^2 extreme points

f (x) = 3 x (x - 5)^{2}

extreme f(x)=(x^2)/(2-x)extreme points

f (x) = \frac{x ^{2}}{2 - x}

extreme f(x)=(2x+5)/3 ,0<= x<= 5 extreme points

f (x) = \frac{2 x + 5}{3}, 0 \leq x \leq 5

extreme y=-5(x-4)^4+2 extreme points

y = - 5 (x - 4)^{4} + 2

extreme x^2+4xy+y^2-40x-56y+1 extreme points

x^{2} + 4 x y + y^{2} - 40 x - 56 y + 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(4x-8)/(x^3) ?
The extreme f(x)=(4x-8)/(x^3) is Maximum(3, 4/27)