What is the extreme (sqrt(4-x^2))/x ?

The extreme (sqrt(4-x^2))/x is Maximum(-2,0),Minimum(2,0)

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extreme (sqrt(4-x^2))/x

extreme points

\frac{4 - x ^{2}}{x}

Maximum (- 2, 0), Minimum (2, 0)

Solution steps

f^{'} (x) = - \frac{4}{x ^{2} 4 - x ^{2}}

Find intervals:

Decreasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2

Plug

x = - 2

into

\frac{4 - x ^{2}}{x} : 0

Maximum (- 2, 0)

Plug

x = 2

into

\frac{4 - x ^{2}}{x} : 0

Minimum (2, 0)

Maximum (- 2, 0), Minimum (2, 0)

f (x) = e^{- k x}

f (x, y) = \frac{( 2 x - x ^{2} ) ( 2 y - y ^{2} )}{x y}

f (x, y) = x^{3} - y^{2} - 12 x + 6 y

f (x) = x^{4} - 8 x^{3} + 4

y = x^{5} - x^{3}

What is the extreme (sqrt(4-x^2))/x ?
The extreme (sqrt(4-x^2))/x is Maximum(-2,0),Minimum(2,0)