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Popular >

extreme 2ln(1+x^2)

Solution

extreme points

2 ln (1 + x^{2})

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{4 x}{1 + x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

2 ln (1 + x^{2}) : 0

Minimum (0, 0)

Popular Examples

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extreme f(x)=sin(x)+cos(x),0<x<2pi extreme points

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extreme f(x)=sin(x),-pi/2 <= x<= (5pi)/6 extreme points

f (x) = sin (x), - \frac{π}{2} \leq x \leq \frac{5 π}{6}

extreme f(x)=x+2y extreme points

f (x) = x + 2 y

extreme y=-x^2+4x extreme points

y = - x^{2} + 4 x

Frequently Asked Questions (FAQ)

What is the extreme 2ln(1+x^2) ?
The extreme 2ln(1+x^2) is Minimum(0,0)