What is the domain of g(x)=sqrt(x-9) ?

The domain of g(x)=sqrt(x-9) is x>= 9

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domain of g(x)=sqrt(x-9)

domain

g (x) = x - 9

x \geq 9

Interval Notation

[9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

The function domain

x \geq 9

x^{2} - 3 x + 2

\frac{1}{2} x + \frac{2}{3} y = - 2

f (x) = x + 6 \cdot x - 1

f (x) = \frac{317 + x}{5}

\frac{x}{- x + 1}