What is the extreme f(x)=2x^3+3x^2-36x+46 ?

The extreme f(x)=2x^3+3x^2-36x+46 is Maximum(-3,127),Minimum(2,2)

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extreme f(x)=2x^3+3x^2-36x+46

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 46

Maximum (- 3, 127), Minimum (2, 2)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 36

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 3

into

2 x^{3} + 3 x^{2} - 36 x + 46 : 127

Maximum (- 3, 127)

Plug

x = 2

into

2 x^{3} + 3 x^{2} - 36 x + 46 : 2

Minimum (2, 2)

Maximum (- 3, 127), Minimum (2, 2)

f (x) = \frac{1 + x ^{2}}{4 - x ^{2}}

y = x^{3} + 4 x^{2} + 5 x - 2

\frac{x - 4}{x ^{2}}

y = 4 sin (2 π (x + (- 45))) + (- 2)

f (x) = x^{4} + 6 x^{5} - x

What is the extreme f(x)=2x^3+3x^2-36x+46 ?
The extreme f(x)=2x^3+3x^2-36x+46 is Maximum(-3,127),Minimum(2,2)