What is the extreme f(x)=6x^5-160x^3+26 ?

The extreme f(x)=6x^5-160x^3+26 is Maximum(-4,4122),Saddle(0,26),Minimum(4,-4070)

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extreme f(x)=6x^5-160x^3+26

extreme points

f (x) = 6 x^{5} - 160 x^{3} + 26

Maximum (- 4, 4122), Saddle (0, 26), Minimum (4, - 4070)

Solution steps

f^{'} (x) = 30 x^{4} - 480 x^{2}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

6 x^{5} - 160 x^{3} + 26 : 4122

Maximum (- 4, 4122)

Plug

x = 0

into

6 x^{5} - 160 x^{3} + 26 : 26

Saddle (0, 26)

Plug

x = 4

into

6 x^{5} - 160 x^{3} + 26 : - 4070

Minimum (4, - 4070)

Maximum (- 4, 4122), Saddle (0, 26), Minimum (4, - 4070)

f (x) = x^{3} - 12 x - 8

f (x) = \frac{- x ^{2} - 1}{( x ^{2} - 1 ) ^{2}}

f (x, y) = 4 x y - x^{2} - y^{2} - 14 x + 4 y + 10

f (x) = 7 x - 2 x ln (x)

f (x) = - x^{3} - 9 x^{2} - 24 x + 2

What is the extreme f(x)=6x^5-160x^3+26 ?
The extreme f(x)=6x^5-160x^3+26 is Maximum(-4,4122),Saddle(0,26),Minimum(4,-4070)