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Popular >

distance (-3,-1),(5,1)

Solution

distance

(- 3, - 1), (5, 1)

Solution

217

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 3, - 1)

and

(5, 1)

is

= (5 - (- 3))^{2} + (1 - (- 1))^{2}

Simplify

= 217

Popular Examples

symmetry y=x^2+4x+4 symmetry

y = x^{2} + 4 x + 4

shift y=3sin(x/3 (-pi)/3)shift

y = 3 sin (\frac{x}{3} \frac{- π}{3})

inflection x/(x^2+1)inflection points

\frac{x}{x ^{2} + 1}

perpendicular 3x-2y=8 perpendicular

3 x - 2 y = 8

extreme f(x)=\sqrt[3]{x}extreme points

Frequently Asked Questions (FAQ)

What is the distance (-3,-1),(5,1) ?
The distance (-3,-1),(5,1) is 2sqrt(17)