What is the extreme f(x)=(e^x)/(x^{10)} ?

The extreme f(x)=(e^x)/(x^{10)} is Minimum(10,(e^{10})/(10^{10)})

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extreme f(x)=(e^x)/(x^{10)}

extreme points

f (x) = \frac{e ^{x}}{x ^{10}}

Minimum (10, \frac{e ^{10}}{1 0 ^{10}})

Solution steps

f^{'} (x) = \frac{e ^{x} ( x - 10 )}{x ^{11}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 10,

Increasing

: 10 < x < \infty

Plug

x = 10

into

\frac{e ^{x}}{x ^{10}} : \frac{e ^{10}}{1 0 ^{10}}

Minimum (10, \frac{e ^{10}}{1 0 ^{10}})

f (x, y) = (x^{2} + y^{2}) (e^{y^{2} - x^{2}})

f (x, y) = e^{x + y}

f (x) = x + x^{3}

f (x) = 3 x^{3} - 4 x

f (x, y) = x^{3} + y^{3} - 3 x^{2} - 3 y

What is the extreme f(x)=(e^x)/(x^{10)} ?
The extreme f(x)=(e^x)/(x^{10)} is Minimum(10,(e^{10})/(10^{10)})