What is the extreme f(x)=-x^4-8x^3-18x^2+7 ?

The extreme f(x)=-x^4-8x^3-18x^2+7 is Saddle(-3,-20),Maximum(0,7)

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extreme f(x)=-x^4-8x^3-18x^2+7

extreme points

f (x) = - x^{4} - 8 x^{3} - 18 x^{2} + 7

Saddle (- 3, - 20), Maximum (0, 7)

Solution steps

f^{'} (x) = - 4 x^{3} - 24 x^{2} - 36 x

Find intervals:

Increasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 3

into

- x^{4} - 8 x^{3} - 18 x^{2} + 7 : - 20

Saddle (- 3, - 20)

Plug

x = 0

into

- x^{4} - 8 x^{3} - 18 x^{2} + 7 : 7

Maximum (0, 7)

Saddle (- 3, - 20), Maximum (0, 7)

f (x, y) = - y^{2} + x y - x^{3} + y + 3

2 - cos (x)

f (x) = x^{\frac{1}{3}} + 2

f (x) = x^{3} - 6 x^{2} + 9 x + 6

f (x, y) = x^{3} + y^{2} - 3 x - 2 y

What is the extreme f(x)=-x^4-8x^3-18x^2+7 ?
The extreme f(x)=-x^4-8x^3-18x^2+7 is Saddle(-3,-20),Maximum(0,7)