en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y=2x^3-3x^2+6

Solution

extreme points

y = 2 x^{3} - 3 x^{2} + 6

Solution

Maximum (0, 6), Minimum (1, 5)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

2 x^{3} - 3 x^{2} + 6 : 6

Maximum (0, 6)

Plug

x = 1

into

2 x^{3} - 3 x^{2} + 6 : 5

Minimum (1, 5)

Maximum (0, 6), Minimum (1, 5)

Popular Examples

extreme f(x)=x^2-2x^4 extreme points

f (x) = x^{2} - 2 x^{4}

extreme f(x)=(x-8)e^x extreme points

f (x) = (x - 8) e^{x}

extreme y=6t^2-42t-60 extreme points

y = 6 t^{2} - 42 t - 60

extreme y=y=(x^3)/3+(x^2)/2-2x+9 extreme points

y = y = \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + 9

extreme-y^2+xy-x^3+y+3 extreme points

- y^{2} + x y - x^{3} + y + 3

Frequently Asked Questions (FAQ)

What is the extreme y=2x^3-3x^2+6 ?
The extreme y=2x^3-3x^2+6 is Maximum(0,6),Minimum(1,5)