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Popular >

extreme f(x)=(-2)/(x^2-9)

Solution

extreme points

f (x) = \frac{- 2}{x ^{2} - 9}

Solution

Minimum (0, \frac{2}{9})

Solution steps

f^{'} (x) = \frac{4 x}{( x ^{2} - 9 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 0,

Increasing

: 0 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 0

into

\frac{- 2}{x ^{2} - 9} : \frac{2}{9}

Minimum (0, \frac{2}{9})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=(-2)/(x^2-9) ?
The extreme f(x)=(-2)/(x^2-9) is Minimum(0, 2/9)