What is the extreme f(x)=2x^3-6x^2 ?

The extreme f(x)=2x^3-6x^2 is Maximum(0,0),Minimum(2,-8)

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extreme f(x)=2x^3-6x^2

extreme points

f (x) = 2 x^{3} - 6 x^{2}

Maximum (0, 0), Minimum (2, - 8)

Solution steps

f^{'} (x) = 6 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

2 x^{3} - 6 x^{2} : 0

Maximum (0, 0)

Plug

x = 2

into

2 x^{3} - 6 x^{2} : - 8

Minimum (2, - 8)

Maximum (0, 0), Minimum (2, - 8)

f (x) = x^{2} - 8 x + 20

π r^{2} + x^{2}

\frac{( x - 1 )}{( x + 1 ) ^{2}}

f (x) = 9 sin (∣ x ∣), - 2 π \leq x \leq 2 π

f (x) = x e^{y}

What is the extreme f(x)=2x^3-6x^2 ?
The extreme f(x)=2x^3-6x^2 is Maximum(0,0),Minimum(2,-8)