What is the extreme f(x)=2x^3-6x^2-18x+1 ?

The extreme f(x)=2x^3-6x^2-18x+1 is Maximum(-1,11),Minimum(3,-53)

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extreme f(x)=2x^3-6x^2-18x+1

extreme points

f (x) = 2 x^{3} - 6 x^{2} - 18 x + 1

Maximum (- 1, 11), Minimum (3, - 53)

Solution steps

f^{'} (x) = 6 x^{2} - 12 x - 18

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

2 x^{3} - 6 x^{2} - 18 x + 1 : 11

Maximum (- 1, 11)

Plug

x = 3

into

2 x^{3} - 6 x^{2} - 18 x + 1 : - 53

Minimum (3, - 53)

Maximum (- 1, 11), Minimum (3, - 53)

y = - 4 x^{3} + 60 x^{2} - 252 x + 8

f (x, y) = 10 - x^{2} y + 3 x y + x y^{2}

2 x^{3} - 9 x^{2} + 12 x

y = \frac{2 x}{x - 6}

f (t) = (e^{t} + 2 t - 1) u (t - 1)

What is the extreme f(x)=2x^3-6x^2-18x+1 ?
The extreme f(x)=2x^3-6x^2-18x+1 is Maximum(-1,11),Minimum(3,-53)