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Popular >

extreme f(x)=x^2-4x+7

Solution

extreme points

f (x) = x^{2} - 4 x + 7

Solution

Minimum (2, 3)

Solution steps

f^{'} (x) = 2 x - 4

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{2} - 4 x + 7 : 3

Minimum (2, 3)

Popular Examples

extreme f(x)=x^4-8x^2-2 extreme points

f (x) = x^{4} - 8 x^{2} - 2

extreme f(x)=4x^3-39x^2+90x+2,1<= x<= 6 extreme points

f (x) = 4 x^{3} - 39 x^{2} + 90 x + 2, 1 \leq x \leq 6

extreme f(x)=-2x^3+9x^2-10x+3 extreme points

f (x) = - 2 x^{3} + 9 x^{2} - 10 x + 3

extreme-5^x extreme points

- 5^{x}

extreme x^2-4x-1 extreme points

x^{2} - 4 x - 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-4x+7 ?
The extreme f(x)=x^2-4x+7 is Minimum(2,3)