What is the extreme f(x)=-((x+4)^2)/((x+1)^2) ?

The extreme f(x)=-((x+4)^2)/((x+1)^2) is Maximum(-4,0)

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extreme f(x)=-((x+4)^2)/((x+1)^2)

extreme points

f (x) = - \frac{( x + 4 ) ^{2}}{( x + 1 ) ^{2}}

Maximum (- 4, 0)

Solution steps

f^{'} (x) = \frac{6 ( x + 4 )}{( x + 1 ) ^{3}}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 4

into

- \frac{( x + 4 ) ^{2}}{( x + 1 ) ^{2}} : 0

Maximum (- 4, 0)

f (x, y) = x e^{- 30 x^{2} - 15 y^{2}}

\frac{- 3}{x ^{2} - 9}

f (x) = x (x - 1)^{3}

2 L W

f (x, y) = x^{2} + y^{2} - 8 y

What is the extreme f(x)=-((x+4)^2)/((x+1)^2) ?
The extreme f(x)=-((x+4)^2)/((x+1)^2) is Maximum(-4,0)