What is the d/(dr)(4k^{3/2}(r/w)) ?

The d/(dr)(4k^{3/2}(r/w)) is (4k^{3/2})/w

What is the first d/(dr)(4k^{3/2}(r/w)) ?

The first d/(dr)(4k^{3/2}(r/w)) is (4k^{3/2})/w

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\frac{d}{d r ( w )} (4 k^{\frac{3}{2}} (\frac{r ( w )}{w}))

\frac{4 k ^{\frac{3}{2}}}{w}

Solution steps

\frac{d}{d r ( w )} (4 k^{\frac{3}{2}} (\frac{r ( w )}{w}))

Treat

k, w

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 k^{\frac{3}{2}} \frac{1}{w} \frac{d}{d r ( w )} (r (w))

Apply the common derivative:

\frac{d}{d r ( w )} (r (w)) = 1

= 4 k^{\frac{3}{2}} \frac{1}{w} \cdot 1

Simplify

4 k^{\frac{3}{2}} \frac{1}{w} \cdot 1 : \frac{4 k ^{\frac{3}{2}}}{w}

= \frac{4 k ^{\frac{3}{2}}}{w}

f (x) = x + 10 1 - x, - 2 \leq x \leq 5

f (x) = 2 x^{3} + x^{2} - 11 x

y = x^{5}

f (x) = 5 y - 5 x + x y - 10

2 x + 4 sin (x)

What is the d/(dr)(4k^{3/2}(r/w)) ?
The d/(dr)(4k^{3/2}(r/w)) is (4k^{3/2})/w
What is the first d/(dr)(4k^{3/2}(r/w)) ?
The first d/(dr)(4k^{3/2}(r/w)) is (4k^{3/2})/w