What is the perpendicular y= 3/2 x+6 ?

The perpendicular y= 3/2 x+6 is y=-2/3 x+b

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perpendicular y= 3/2 x+6

perpendicular

y = \frac{3}{2} x + 6

y = - \frac{2}{3} x + b

Solution steps

Find the slope of

y = \frac{3}{2} x + 6 : m = \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{3}

Line with slope m=

- \frac{2}{3} : y = - \frac{2}{3} x + b

y = - \frac{2}{3} x + b

(2.5) (2.1)

y = x^{2} - 1

f (x) = \frac{2 ^{2} - 7 x - 4}{x ^{2} + x - 2}

Q (x, y) = 3 x^{2} + 2 y^{2} x + y = 5

25 - (t^{2} + 9)

What is the perpendicular y= 3/2 x+6 ?
The perpendicular y= 3/2 x+6 is y=-2/3 x+b