What is the extreme f(x,y)=5x^2+5y^2+3 ?

The extreme f(x,y)=5x^2+5y^2+3 is Minimum(0,0)

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extreme f(x,y)=5x^2+5y^2+3

extreme points

f (x, y) = 5 x^{2} + 5 y^{2} + 3

Minimum (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 10

D (x, y) = 100

Check the sign of at each critical point

Check critical point

(0, 0) :

Minimum

Minimum (0, 0)

f (x) = \frac{x - 2}{x + 2}

x + \frac{25}{x}

f (x) = 2 x^{3} - 3 x + 10

y = x^{2} + 2 x - 3

e^{x} (2 x^{2} + x - 8)

What is the extreme f(x,y)=5x^2+5y^2+3 ?
The extreme f(x,y)=5x^2+5y^2+3 is Minimum(0,0)