What is the extreme f(x)=2x^3+18x^2+54x+50 ?

The extreme f(x)=2x^3+18x^2+54x+50 is Saddle(-3,-4)

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extreme f(x)=2x^3+18x^2+54x+50

extreme points

f (x) = 2 x^{3} + 18 x^{2} + 54 x + 50

Saddle (- 3, - 4)

Solution steps

f^{'} (x) = 6 x^{2} + 36 x + 54

Find intervals:

Increasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

2 x^{3} + 18 x^{2} + 54 x + 50 : - 4

Saddle (- 3, - 4)

f (x) = 6 x^{2} - 2 x - 4

f (x, y) = x y + \frac{9}{x} + \frac{3}{y}

f (x) = \frac{1}{2} (e^{x} + e^{- x})

f (x) = 2 x^{2} - 4 x^{4}

x^{3} + 6 x^{2} - 63 x + 10

What is the extreme f(x)=2x^3+18x^2+54x+50 ?
The extreme f(x)=2x^3+18x^2+54x+50 is Saddle(-3,-4)