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Popular >

extreme f(x)= 3/(x^2-4x-5)

Solution

extreme points

f (x) = \frac{3}{x ^{2} - 4 x - 5}

Solution

Maximum (2, - \frac{1}{3})

Solution steps

f^{'} (x) = - \frac{3 ( 2 x - 4 )}{( x ^{2} - 4 x - 5 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 2,

Decreasing

: 2 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = 2

into

\frac{3}{x ^{2} - 4 x - 5} : - \frac{1}{3}

Maximum (2, - \frac{1}{3})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)= 3/(x^2-4x-5) ?
The extreme f(x)= 3/(x^2-4x-5) is Maximum(2,-1/3)