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Popular >

extreme y=x^3-3x^2+4

Solution

extreme points

y = x^{3} - 3 x^{2} + 4

Solution

Maximum (0, 4), Minimum (2, 0)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

x^{3} - 3 x^{2} + 4 : 4

Maximum (0, 4)

Plug

x = 2

into

x^{3} - 3 x^{2} + 4 : 0

Minimum (2, 0)

Maximum (0, 4), Minimum (2, 0)

Graph

Popular Examples

extreme f(x)=1-2x^2 extreme points

f (x) = 1 - 2 x^{2}

extreme f(x,y)=2x^4-2xy+y^2-2 extreme points

f (x, y) = 2 x^{4} - 2 x y + y^{2} - 2

extreme f(x)=1-x^3 extreme points

f (x) = 1 - x^{3}

extreme sqrt(-14-x)extreme points

- 14 - x

extreme f(x,y)=3xy-x^3-y^3 extreme points

f (x, y) = 3 x y - x^{3} - y^{3}

Frequently Asked Questions (FAQ)

What is the extreme y=x^3-3x^2+4 ?
The extreme y=x^3-3x^2+4 is Maximum(0,4),Minimum(2,0)