What is the extreme f(x)=x^3+3x^2+9 ?

The extreme f(x)=x^3+3x^2+9 is Maximum(-2,13),Minimum(0,9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3+3x^2+9

extreme points

f (x) = x^{3} + 3 x^{2} + 9

Maximum (- 2, 13), Minimum (0, 9)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

x^{3} + 3 x^{2} + 9 : 13

Maximum (- 2, 13)

Plug

x = 0

into

x^{3} + 3 x^{2} + 9 : 9

Minimum (0, 9)

Maximum (- 2, 13), Minimum (0, 9)

f (x) = - x^{3} + 3 x + 2

f (x) = 4 x^{6} - 3 x^{5}

f (x, y) = 4 - x^{2} + 4 y^{2}

f (x) = 3 x^{4} + 9 x^{3} + 11

f (x) = 2 x^{3} - 3 x^{2} + 1, - 1 \leq x \leq 3

What is the extreme f(x)=x^3+3x^2+9 ?
The extreme f(x)=x^3+3x^2+9 is Maximum(-2,13),Minimum(0,9)