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Popular >

extreme f(x)=(4x)/(x^2-9)

Solution

extreme points

f (x) = \frac{4 x}{x ^{2} - 9}

Solution

None

Solution steps

f^{'} (x) = \frac{4 ( - x ^{2} - 9 )}{( x ^{2} - 9 ) ^{2}}

Find intervals:

None

None

Graph

Popular Examples

extreme f(x,y)=sqrt(20-x^2-7y^2)extreme points

f (x, y) = 20 - x^{2} - 7 y^{2}

extreme y=3x^2-x-2 extreme points

y = 3 x^{2} - x - 2

extreme f(x,y)=4y^3+x^2-12y^2-36y+2 extreme points

f (x, y) = 4 y^{3} + x^{2} - 12 y^{2} - 36 y + 2

extreme f(0.7)=17e^{-1/6 xy}extreme points

f (0.7) = 17 e^{- \frac{1}{6} x y}

extreme f(x,y)=x^2+y^2-9 extreme points

f (x, y) = x^{2} + y^{2} - 9

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(4x)/(x^2-9) ?
The extreme f(x)=(4x)/(x^2-9) is None