What is the critical f(x)=x^2ln(x) ?

The critical f(x)=x^2ln(x) is x= 1/(sqrt(e))

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critical f(x)=x^2ln(x)

critical points

f (x) = x^{2} ln (x)

x = \frac{1}{e}

Solution steps

x^{2} ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} ln (x) : x > 0

x^{2} ln (x)

is not defined at

x = 0

, therefore:

x = \frac{1}{e}

\frac{3 x ^{2}}{∣ x - 1 ∣}

\frac{d}{d x} (\frac{x y}{x ^{2} + y ^{2}})

f (x, y) = 9 - (x^{2} + y^{2} - 4)^{2}

f (x, y) = x^{2} y - x^{2} - 2 y^{2}

f (x) = x^{3} - 3 x + 2

What is the critical f(x)=x^2ln(x) ?
The critical f(x)=x^2ln(x) is x= 1/(sqrt(e))