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Popular >

midpoint (8,-5),(4,3)

Solution

midpoint

(8, - 5), (4, 3)

Solution

(6, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (8, - 5), (x_{2}, y_{2}) = (4, 3)

= (\frac{4 + 8}{2}, \frac{3 - 5}{2})

Refine

= (6, - 1)

Popular Examples

domain of 2^{x-2}domain

2^{x - 2}

distance (12,5),(-12,-2)distance

(12, 5), (- 12, - 2)

inverse of f(x)=10*((43+x)/(4000))inverse

f (x) = 10 \cdot (\frac{43 + x}{4000})

domain of 3(4x-1)+5 domain

3 (4 x - 1) + 5

inverse of f(x)=x^3+7 inverse

f (x) = x^{3} + 7

Frequently Asked Questions (FAQ)

What is the midpoint (8,-5),(4,3) ?
The midpoint (8,-5),(4,3) is (6,-1)