What is the critical f(x)=2x^2+y^4-4xy ?

The critical f(x)=2x^2+y^4-4xy is (0,0),(-1,-1),(1,1)

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critical f(x)=2x^2+y^4-4xy

critical points

f (x) = 2 x^{2} + y^{4} - 4 x y

(0, 0), (- 1, - 1), (1, 1)

Solution steps

2 x^{2} + y^{4} - 4 x y

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (- 1, - 1), (1, 1)

f (x) = x^{2} + 2 x - 3

g (x) = I n^{3} x

f (x) = \frac{e ^{x}}{x}

f (x, y) = 4 x y - x^{4} - y^{4}

f (x, y) = 2 x^{4} + y^{2} - x^{2} - 2 y

What is the critical f(x)=2x^2+y^4-4xy ?
The critical f(x)=2x^2+y^4-4xy is (0,0),(-1,-1),(1,1)